A force `F=(y^(2)+2y+5)`N acts on a block in positive y- direction.Find the work done by this force during a displacement from y=-1m to y=+1m .

A force F=(10+0.5 x) acts on a particle in the x-direction. What would be the work done by this force during a displacement from x=0 to x=2m (F is in newton and x in metre)

A force F = (10 +0.25x ) is acting on a particle moving along positive X direction . Calculate the work done by this force during a displacement from x = 1 m to x = 4 m .

A force F=(a+bx) acts on a particle in x direction where a and b are constants . Find the work done by this force during displacement from x_(1) to x_(2) .

A force F=a+bx acts on a particle in x-direction, where a and b are constants. Find the work done by this force during the displacement from x_1 to x_2 .

A force F=(2+x) acts on a particle in x-direction where F is in newton and x in metre. Find the work done by this force during a displacement form 1. 0 m to x = 2.0 m.

A force F=(5+2x) acts on a particle in x direction where F is in newtown and x is meter. Find the work done by this force during displacement from x=0 to x=1m.

A force F = Ay^(2)+By+C acts on a body at rest in the Y -direction. The kinetic energy of the body during a displacement y = -a to y = a is

A force F=(15+0.50x) acts on a particle in the X-direction ,where F is in newton and x in metre Find the work done ' by this force during a displacement from x=0 to x=2.0 m .

A force F=(10+0.50x) acts on a particle in the x direction, where F is in newton and x in meter./find the work done by this force during a displacement form x=0 tox=2.0m