If the line "4y-3x-8=0" cuts the parabol...

If the line "`4y-3x-8=0`" cuts the parabola "`x^(2)+y-4=0`" at "A" and "B" .and "`|PA.PB|`" is equal to "`(k)/(8)`" where "`P=(0,2)`" then the value of "k" is.

Similar Questions

Explore conceptually related problems

If the line 2x+3y+k=0 touches the parabola x^(2)=108y then k =

The focus of the parabola y^(2)-4y-8x+4=0 is,

If the line y-sqrt(3)x+3=0 cuts the parabola y^(2)=x+2 at A and B, then find the value of PA.PB { where P=(sqrt(3),0)}

If the line x-3y+k=0 touches the parabola 3y^(2)=4x then the value of k is

If the line k^(2)(x-1)+k(y-2)+1=0 touches the parabola y^(2)-4x-4y+8=0 , then k can be

If the line ax+by+c=0 is a tangent to the parabola y^(2)-4y-8x+32=0, then :

A line is drawn through the point P(3,11) to cut the circle x^(2)+y^(2)=9 at A and B. Then PA.PB is equal to

If the line x-1=0 is the directrix of the parabola y^(2)-kx+8=0 then "k" is A.) 3 B.)-3 C.)4 D.)5