In the reaction `Cr_(2)S_(3)`+`Mn^(+2)`+`NO_(3)^(-)`+`CO_(3)^(-2)` `rarr` `CrO_(4)^(2)`+`MnO_(4)^(2)`+`NO`+`CO_(2)`+`SO_(4)^(2-)` The elements that undergo oxidation

In the reaction C_(2)O_(4)^(2-)+MnO_(4)^(-)+H^(+) rarr Mn^(2+)+CO_(2)+H_(2)O the reductant is

In the reaction C_(2) O_(4)^(-2) + MnO_(4)^(-) + H^(+) rarr Mn^(+2) +CO_(2) the reductants is -

(b ) Draw the structures of Cr_(2) O_(7)^(2-) , CrO_(4)^(-2) MnO_(4)^(-)

In the reaction MnO_(4)^(-)+SO_(3)^(-2)+H^(+)rarrSO_(4)^(-2)+Mn^(2+)+H_(2)O

Consider the following reactions : (i) C_(2)O_(4)^(2-) rarr CO_(2) (ii) SO_(4)^(2-) rarr SO_(3)^(2-) (iii) MnO_(4)^(2-) rarr MnO_(4)^(-) (iv) Fe^(3+) rarr Fe^(2+) Choose the correct answer -

FeCr_(2)O_(4)+Na_(2)CO_(3)+O_(2) to Fe_(2)O_(3)darr+Na_(2)CrO_(4)

Cr_(2)O_(5)^(-2)rarr CrO_(4)^(-2) In the above reaction the change in oxidation number is

2mNo_(4)^(2-)+cl _(2) rarr Mn^(2+)+5Fe^(3+) MnO_(4)^(2-) can be converted to MnO_(4)^(-)