A body is thrown with an initial velocity "sqrt(3)hat i+1hat j" .Its angle of projection is

A projectile is thrown with an initial velocity of v = a hat i + b hat j . If the range of projectile is double the maximum height reached by it. Find the ratio (b)/(a) .

A body of mass 5 kg statrs from the origin with an initial velocity vec(u) = (30 hat(i) + 40 hat(j)) ms^(-1) . If a constant force (-6 hat(i) - 5 hat(j))N acts on the body, the time in which they component of the velocity becomes zero is

A body of mass 5 kg starts from the origin with an intial with an intial velocity vec (u) = 30hat(i) + 40hat(j). . If the body collides with a wall and after collision its velocity becomes vec(v) = - 30 hat (i) + 40 hat (j) , then what is change in momentum of body ?

A projectile is given an initial velocity of ( hat(i) + 2 hat (j) ) m//s , where hat(i) is along the ground and hat (j) is along the vertical . If g = 10 m//s^(2) , the equation of its trajectory is :

A particle has initial velocity (3 hat i+ 4 hat j) and has acceleration (0.1 hat i+ 0.3 hat j) . Its speed after 10 s is.

A particle has an initial velocity of 3hat(i) + 4 hat(j) and an acceleration of 0.4 hat(i) + 0.3 hat(j) . Its speed after 10s is :

A particle has an initial velocity (2 hat(i) + 3 hat(j)) and an accelaration (0.3 hat(i) + 0.2 hat(j)) . The magnitude of velocity after 10 s will be

A force of 6 hat i+ 7 hat j newton makes a body move on a rough loane with a velocity of (4 hat j = 3 hat k) ms^(-1) . Calculate the power in watt.

If overset(rarr)A=2 hat i + 3 hat j- hat k and overset(rarr)B=-hat i+3 hat j +4 hat k and then projection of overset(rarr)A on overset(rarr)B will be :

The velocity of a projectile at the initial point A is (2hat(i)+3hat(j))m//s .Its velocity (in m//s) at point B is