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The spring is compressed by a distance a...

The spring is compressed by a distance a and released. The block again comes to rest when the spring is elongated by a distance `b`. During this

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A spring of stiffness 2KN/m is attached to a block of mass 8kg on a surface that has frictional co-efficient 0.4 .The spring is compressed and released,and the block accelerates at 4m/s^(2) just as it is released. The work done in compressing the spring is:

For the system shown in fig., initially the spring is compressed by a distance 'a' from its natural length and when released, it moves to a distance 'b' from its equillibrium position, the decrease in amplitude for half cycle (-a to +b) is :

In the figure shown the spring is compressed by 'x_(0)' and released . Two block 'A' and 'B' of masses 'm' and '2m' respectively are attached at the ends of the spring. Blocks are kept on a smooth horizontal surface and released. Find the work done by the spring on 'A' by the time compression of the spring reduced to (x_(0))/(2) .

A block of mass m is pushed up against a spring, compressing it a distance x , and the block is then released. The spring projects the block along a frictionaless horizontal surface, grving the block a speed v . The same spring projects a second block of mass 4m , giving it a speed 3v . What distance was the spring compressed in the second case ?

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In figure a spring with k = 168 N//m is in its relaxed length and is at the top of a frictionless incline of angle theta = 37^(@) . The lower end of the incline is at distance D = 1 m from the end of the spring. A small blcok of mass 2 kg is pushed against the spring until the spring is compressed by 0.2 m and released from rest. What is the speed of the block at the instant the spring returns to its relaxed length (which is when the block loses contact with the spring)?

The block shown in figure is released from rest. Find out the speed of the block when the spring is compressed by 1 m