The dimensions of `'k'` in the relation `V = k` avt (where `V` is the volume of a liquid passing through any point in time `t, 'a'` is area of cross section, `v` is the velocity of the liquid) is

Find the dimension of (a/b) in the equation : v = a + bt , where v is velocity and t is time

The dimensions of gamma in the relation v = sqrt((gamma p)/(rho)) (where v is velocity, p is pressure , rho is density)

Find the dimensions of V in the equation y= A sin omega((x)/(V)-k)

An incompressible liquid flows through a horizontal tube LMN as shown in the figure. Then the velocity V of the liquid throught he tube N is:

A liquid of density rho comes out with a velocity v from a horizontal tube of area of cross-section A. The reaction force exerted by the liquid on the tube is F :

An engine pumps liquid of density d continuosly through a pipe of cross-section are A. If the speed with which liquid passes through the pipe is v, then the rate at which kinetic energy is being imparted to the liquid by the pump is

A liquid is flowing through a pipe of non-uniform cross-section. At a point where area of cross-section of the pipe is less, match the following columns.

The rate of volume of flow of water (V) through a canal is found to be a function of the area of cross section A of the canal and velocity of water v. Show that the rate of volume flow is proportional to the velocity of flow of water.