The potential energy of a particle varies with distance 'x' as U=(Ax^(1/2))/(x^(2)+B),where A and B are constants.The dimensional formula for A times B is [M^(a)L^(b)T^(c)] then a=

The potential energy of a particle varies with distance x from a fixed origin as V= (Asqrt(X))/(X + B) where A and B are constants . The dimension of AB are

Hydrostatic pressure 'P' varies with displacement 'x' as P = (A)/(B)log(Bx^(2) +C) where A,B, and C are constants. The dimensional formula for 'A' is

The energy E of a particle at position x at time t is given by E=a/(t(b+x^(2)) Where a and b are constants. The dimensional formula of a is

The potential energy of a particle depends on its x-coordinates as U=(Asqrt(x))/(x^2 +B) , where A and B are dimensional constants. What will be the dimensional formula for A/B?

The potential energy of a particle varies with distance x from a fixed origin as U = (A sqrt(x))/( x^(2) + B) , where A and B are dimensional constants , then find the dimensional formula for AB .

The potential energy (U) of a particle can be expressed in certain case as U=(A^(2))/(2mr^(2))-(BMm)/(r) Where m and M are mass and r is distance. Find the dimensional formulae for constants.

The potential energy of a particle is given by formula U=100-5x + 100x^(2), where U and are .

The work done 'w' by a body varies with displacement 'x' as w=Ax+(B)/(c-x)^(2) .The dimensional formula for B is