The maximum K.E found in alpha particle of natural origin is 7.7MeV.Find the closest distance of approach for the gold nucleus.(Z = 79 for gold)

The K.E. of alpha -particle incident gold foil is doubled. How does the distance of closest approach change?

Find the distance of closest approach when a 6 MeV proton approaches a gold nucleus.

Calculate the energy of an alpha -particle whose distance of closest approach with the gold nucleus is 29.5 fermi.

When an alpha particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach form the nucleus depends on m as

Calculate the impact parameter of a 5MeV alpha particle scatterd by 10^@ when it approaches a gold nucleus. Take Z=79 for gold.

What is the distance of closest approach when a 5.0 MeV proton approaches a gold nucleus?

A closest distance of approach of an "alpha" particle travelling with a velocity "v towards "Al(13)" nucleus is d The closest distance of approach of an alpha particle travelling with velocity 4V towards Fe(26) nucleus is