What is the work done by 0.2 mole of a gas at room temperature to double its volume during isobaric process? (Take R=2 cal `mol^(-1).^(@)C^(-1)`)

Calculate the work done by 0.1 mole of a gas at 27^(@)C to double its volume at constant pressure (R = 2 cal mol^(-1)K^(-1))

Work done by 0.1 mole of a gas at 27^@ C to double its volume at constant pressure is (use R=2 cal/mol ""^(@) C)

Work done by 0.1 mole of a gas at 27^(@)C to double its volume at constant pressure is (R=2" cal mol"^(-1).^(@)K^(-1))

Calculate the work done by 1 mole of gas if temperature is changed from O^circC to 200^circC at one atmosphere ( R =2 cal K^-1 mole^-1').

The work done by 1 mole of ideal gas during an adiabatic process is (are ) given by :

A gram mole of a gas at 27^@C expands isothermally until its volume is doubled. Calculate the amount of work done. (R=8 J mol^(-1) K^(-1))

Determine the quantity of heat added to 3.5 moles of the ideal gas argon if the temperature increases from 75 ^@ C to 225^@ C during an isobaric process . (the molar specific of argon are C_v = 3.0 cal // K mol and C_P = 5.0 cal // K mol )

If one mole of gas doubles its volume at temperature T isothermally then work done by the gas is

Define an adiabatic process and state essential conditions for such a process to take place. Write its process equations in terms of , and . Show analytically that work done by one mole of an ideal gas during adiabatic expansion from temperature T_1 to T_2 is given by = (R(T_1 - t_2))/(1-lamda ) .