The arithmetic mean of `""^(n)C_(0),""^(n)C_(1),""^(n)C_(2), ..., ""^(n)C_(n)`, is

The mean of then Numbers 0,1,2,3.......n with respective weights ""^(n)C_(0),""^(n)C_(1),""^(n)C_(2)........""^(n)C_(n) is

3""^(n)C_(0)+10""^(n)C_(1)+28""^(n)C_(2)+82""^(n)C_(3)+…(n+1) terms =

Consider the date on x taking the values 0,2,4,8,………., 2^(n) with frequencies ""^(n)C_(0) , ""^(n)C_(1), ""^(n)C_(2),……..,""^(n)C_(n) respectively . If the mean of this data is (728)/(2^(n)) then n is equal to ________.

If n is an odd natural number and ""^(n)C_(0)lt ""^(n)C_(1)lt ""^(n)C_(2)lt ...lt ""^(n)C_(r) gt ""^(n)C_(r+1) gt ""^(n)C_(r+2) gt ...gt""^(n)C_(n) , then r=

The arithmetic mean of the following frequency distribution: {:("Variate(X)" ,:,0,1,2,3, ..., n),("Frequency" (f),:,""^(n)C_(0),""^(n)C_(1),""^(n)C_(2),""^(n)C_(3),...,""^(n)C_(n)):} is

The value of ""^(n)C_(n)+""^(n+1)C_(n)+""^(n+2)C_(n)+….+""^(n+k)C_(n) :

What is ""^(n)C_(1)+ ""^(n)C_(2)+……… + ""^(n)C_(n) ?