A particle is projected with a velocity of `20sqrt(3) ms^(-1)` at an angle of `60^(@)` to the horizontal. At the moment, the direction of motion of the projectile is perpendicular to the direction of initial velocity of projection, its velocity is

An object is projected with a velocity of 30 ms^(-1) at an angle of 60^(@) with the horizontal. Determine the horizontal range covered by the object.

A particle is projected with a velocity of 20 ms^(-1) at an angle of 60^(@) to the horizontal. The particle hits the horizontal plane again during its journey. What will be the time of impact ?

Two particle are projected with same initial velocities at an angle 30^(@) and 60^(@) with the horizontal .Then

A particle is projected with speed 100m/s at angle theta=60^(@) with the horizontal at time t=0" . At time 't' the velocity vector of the particle becomes perpendicular to the direction of velocity of projection.Its tangential acceleration at time 't' is (g =10m/s^(2))

A ball is thrown with velocity 8 ms^(-1) making an angle 60^(@) with the horizontal.Its velocity will be perpendicular to the direction of initial velocity of projection after a time of

A particle is projected upwards with a velocity of 110m/sec at an angle of 60^(@) with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking g =10m//sec^(2)