A body projected just crosses a wall of 4m height,at 6m distance from the point of projection and it hits the ground at 12m away from the wall. The angle of projection is nearly

A body projected from a point O at an angle theta , just crosses a wall y m high at a distance. x m from the point of projection and strikes the ground at Q beyond the wall as shown, then find height of the wall

A ball is projected at an angle 45^(@) with horizontal. It passes through a wall of height h at horizontal distance d_(1) from the point of projection and strikes the ground at a horizontal distance (d_(1) + d_(2)) from the point of projection, then

A ball is thrown from the ground to clear a wall 3 m high at a distance of 6 m and falls 18 m away from the wall the angle of projection of ball is :-

A ball is thrown from the ground so that it just crosses a wall 5m high at a distance of 10m and falls at a distance of 10m ahead from the wall. Find the speed and the direction of projection of ball. Assume, g = 10" ms"^(–2)

A particle just clears a wall of height b at distance a and strikes the ground at a distance c from the point of projection.The angle of projection is (1)tan^(-1)(b)/(ac)(2) (3) tan^(-1)(bc)/(a(c-a))(4)tan^(-1)(bc)/(a)

A ball is thrown from the ground to clear a wall 3 m high at a distance of 6 m and falls 18 m away from the wall. Find the angle of projection of ball.

A ball is thrown from the ground to clear a wall 3m high at a distance of 6m and falls 18m away from the wall, the angle of projection of ball is tan^(-1)(2/x) . Find value of x .

A ball is thrown from the ground so as to just clear a wall 10 m high at a distance of 20 m and falls at a distance of 40 m from the wall. The magnitude and direction of the projection velocity is