For a projectile the ratio of the square of the time of flight to its maximum height is (A) 5:4 (B) 5:2 (C) 4:5 (D) 10:1

For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10 ms^(-2))

Range of a projectile with time of flight 10 s and maximum height 100 m is : (g= -10 m//s ^2)

Ratio between maximum range and square of time of flight in projectile motion is

A square is inscribed in a circle and another in a semi-circle of same radius.The ratio of the area of the first square to the area of the second square is (a) 2:5quad (b) 5:2 (c) 4:5quad (d) 5:4

A particle is thrown with speed of 50 m//s at an angle of projection 37^(@) with the horizontal. Find (a) the time of flight, (b) the maximum height attained and ( c) the horizontal range. (sin 37^(@) = (3)/(5), cos 37^(@) = (4)/(5))

If each side of a square is increased by 50%, the ratio of the area of the resulting square to that of the given square is (a) 4 : 5 (b) 5 : 4 (c) 4 : 9 (d) 9 : 4

If the volumes of two cones are in the ratio 1:4 and their diameters are in the ratio 4:5, then the ratio of their heights, is (a) 1:5 (b) 5:4 (c) 5:16 (d) 25:64

The ratio 384:480 in its simplest form is (a) 3:5 (b) 5:4 (c) 4:5 (d) 2:5

Find the angle of projection for a projectile if its speed at maximum height is sqrt(5//9) times its speed at one-third of maximum height (g=10ms^(-2))