A projectile is fired with 10ms^-1 at an angle of 60o with horizontal.During its motion,its velocity,when it makes 30o to horizontal is

A projectile is projected at 10ms^(-1) by making an angle 60^(@) to the horizontal. After sometime, its velocity makes an angle of 30^(@) to the horzontal . Its speed at this instant is:

A projectile is thrown with a velocity of 10 ms^(-1) at an angle of 60^(@) with horizontal. The interval between the moments when speed is sqrt(5g) m//s is (Take, g = 10 ms^(-2))

A projectile is fired with a speed u at an angle theta with the horizontal. Find its speed when its direcrtion of motion makes an angle alpha with the horizontal.

A particle is projected with speed 'u' at an angle 60^@ with horizontal, then find the speed when its angle with horizontal changes to 30^@ .

A projectile is thrown with a velocity of 10ms^(-1) at an angle of 30o with horizontal.The value of maximum height gained by it is (a) 1m(b) 1.25m (c) 2m

A particle is projected with a velocity of 20 ms^(-1) at an angle of 60^(@) to the horizontal. The particle hits the horizontal plane again during its journey. What will be the time of impact ?

A projectile is fired at an angle of 30^(@) to the horizontal such that the vertical component of its initial velocity is 80m//s . Its time of fight is T . Its velocity at t=T//4 has a magnitude of nearly.