If the binding energy per nucleon in `L i^7` and `He^4` nuclei are respectively `5.60 MeV` and `7.06 MeV`. Then energy of reaction `L i^7 + p rarr 2_2 He^4` is.

If the binding energy per nucleon in ._(3)Li^(7) and ._(2)He^(4) nuclei are respectively 5.60 MeV and 7.06 MeV, then the energy of proton in the reaction ._(3)Li^(7) +p rarr 2 ._(2)He^(4) is

If the binding energy per nucleon in _(3)^(7) Li and _(2)^(4)He nuclei are 5.60 MeV and 7.06MeV respectively then in the reaction P +_(3)^(7) Li rarr 2 _(2)^(4) He energy of proton mnust be

If the binding energy per nucleon in ._(3)^(7)Li and ._(2)^(4)He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction p+._(3)^(7)Lirarr2._(2)^(4)He energy of proton must be:

The binding energy per nucleon of ._(3)^(7) Li and ._(2)^(4)He nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction ._(3)^(7)Li+._(1)^(1)H rarr ._(2)^(4)He+._(2)^(4)He+Q , the value of energy Q released is

Calculate the energy of the reaction , Li^(7) + p to 2 _(2)He^(4) If the binding energy per nucleon in Li^(7) and He^(4) nuclei are 5.60 MeV and 7.06 MeV , respectively .

The binding energy per nucleon for ""_(1)H^(2) and ""_(2)He^(4) are 1.1 MeV and 7.1 MeV respectively. The energy released when two ""_(1)H^(2) to form ""_(2)He^(4) is ………….. MeV.

In the reaction ._1^2 H + ._1^3 H rarr ._2^4 He + ._0^1 n , if the binding energies of ._1^2 H, ._1^3 H and ._2^4 He are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is.