A body is thrown vertically upward with velocity u. The distance travelled by it in the `7^(th) and 8^(th)` seconds are equal. The displacement in `8^(th)` seconds is equal to (take `g=10m//s^(2)`)

A body is thrown vertically upward with velocity u . The distance traveled by it in the fifth and the sixth second are equal. The velocity u is given by

A body starts from rest. What is the retio of the distance traveled by the body during the 4^(th) and 3^(rd) seconds

A body thrown vertically upward,such that the distance travelled by it in fifth and sixth seconds are equal.The maximum height reached by the body is (A) 30m (B) 60m (C) 125m (D) 120m

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m//s . The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is ("Take" g = 10 m//s^2) .

If a particle is thrown vertically upwards , then its velocity so that it covers same distance in 5th and 6th seconds would be .

A particle is thrown vertically upward with speed 45 m//s . Find the distance covered by the particle in the 5^(th) second of its journey.

A body is thrown vertically upwards and takes 5 seconds to reach maximum height. The distance travelled by the body will be same in :-