Home
Class 11
MATHS
Two points A and B move on the positive ...

Two points A and B move on the positive direction of x-axis and y-axis respectively, such that OA + OB K. Show that the locus of the foot of the perpendicular from the origin O on the line ABís (x + y)(x2 + y2) = Kxy. · (0,b)B Let the equation of AB be =1 a

Promotional Banner

Similar Questions

Explore conceptually related problems

The locus of the foot of the perpendicular from the foci an any tangent to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 , is

Let A be the foot of the perpendicular from the origin to the plane x-2y+2z+6=0 and B(0, -1, -4) be a point on the plane. Then, the length of AB is

What are the points on the x-axis whose perpendicular distance from the line (x)/(a)+(y)/(b)=1 is a

A and B are any two points on the positive x and y axis respectively satisying 2(OA)+3(OB)=10.1fP is the middle point of AB then the locus of P is-

Find the points on the X-axis whose perpendicular distance from the line x/a+y/b=1 is a

A circle of constant radius 5 units passes through the origin O and cuts the axes at A and B. Then the locus of the foot of the perpendicular from O to AB is (x^(2)+y^(2))^(2)(x^(-1)+y^(-2))=k then k=

The locus of foot of perpendicular from focus of ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 to its tangents is

Find the length of the foot of perpendicular drawn from the point P(a, b, c) on x-axis, y-axis and z-axis respectively.