Consider the parametrically defined curve `x(t)=1-sint,y=4-3cos t` then the equation in cartesian form is given by.

The curve with parametric equations x=1+4 cos theta, y=2+3 sin theta is

If the parametric of a curve given by x=e^(t)cos t, y=et sin t , then the tangent to the curve at the point t=pi//4 makes with axis of x the angle

Consider the parametric equation x=(a(1-t^(2)))/(1+t^(2))" and "y=(2at)/(1+t^(2)) What does the equation represent ?

The parametric equation of a parabola is x=t^(2)+1,y=2t+1. Then find the equation of the directrix.

Find the equation of the tangent to the curve x=sin3t , y=cos2t at t=pi/4 .

The length of the normal at t on the curve x=a(t+sint), y=a(1-cos t), is

The curve with parametric equations x=1 +4cos theta , y= 2 +3 sin theta . is

Find the equation of tangent to the curve x=sin3t,y=cos2tquad at t=(pi)/(4)