Let `vec a=vec i-vec j+3vec k,vec b=3vec i-5vecj+6veck` integer part of the magnitude of the projection of `2vec a-vec b` on to the vector `vec a+vec b` is

Let veca=vec(i)-vec(j)+3vec(k),vec(b)=3vec(i)-5vec(j)+6vec(k) .Then integer part of the magnitude of the projection of 2vec a-vec b on to the vector vec a+vec b is

Let vec a=4vec i+3vec j and vec b=3vec i+4vec j . Find the magnitudes of (a)vec a,(b)vec b,(c)vec a+vec b" and (d)vec a-vec b

The position vectors of the points A and B are vec i + 2 vec j + 3 vec k and 2 vec i - vec j - vec k respectively. Find the projection of vec (AB) on the vector vec i + vec j + vec k . Also find the resolved part of vec (AB) in that direction.

vec a = vec i + 2vec j + 3vec k, vec b = -vec i + 2vec j + vec k, rArr3vec i + vec j and vec d is normal to both vec a and vec b then (vec c, vec d)

If vec a = vec i + vec j + vec k, vec b = vec i - vec j + vec k and vec c = vec i + 2vec j - vec k, then the value of | [vec a.vec a, vec a.vec b, vec a.vec c], [vec b.vec a, vec b.vec b, vec b.vec c], [vec c.vec a, vec c.vec b, vec c.vec c ] | is equal to: (1) 2 (2) 4 (3) 16 (4) 64

vec a=2vec i+3vec j-vec k,vec b=-vec i+2vec j-4vec k and vec c=vec i+vec j+vec k then find thevalue of (vec a xxvec b)*(vec a xxvec c)

If a=vec i+4vec j,vec b=2vec i-3vec j and vec c=5vec i+9vec j then vec c=

If vec a = 2vec i-3vec j + vec k and vec b = -vec i + vec kvec c = 2vec j-vec k then the area of the parallelogram is having diagonals vec a + vec b and vec b + vec c is

If vec a=hat i-hat j and vec b=-hat j+hat k find the projection of vec a on vec b

Let vec a = vec i + vec j, vec b = vec j + vec kc = alphavec a + betavec b .If the vectors vec i-2vec j + vec k, 3vec i + 2vec j-vec k and vec c are coplanar then aplh (a) / (beta)