A particle starts from rest at the origin and moves along the positive x direction. Its acceleration a versus position x graph is shown in the figure. The velocity of the particle at x = 6 m is?

Velocity (v) versus position (x) graph of a particle is shown.The acceleration of the particle at x=1m is ?

A particle starts from the origin at time t = 0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s ?

A particle starting from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be.

A particle starts moving from rest in a from rest in a straight line. Its acceleration vs time (a - t) graph is shown in figure. The speed of particle is maximum at.

A particle starts moving from rest the origin & moves along positive x- direction . Its rate of change of kinetic energy with time shown on y- axis veries with time t as shown in the graph. If position, velocity , acceleration & kinetic energy of the particle at any time t are x,v,a,& k respectively then which of the option (s) may be correct ?

A particle starts to move along a straight line. The acceleration versus time graph of particle is as shown in figure. The correct velocity versus time graph is :

The acceleration of a particle which moves along the positive x-axis varies with its position as shown in figure. If the velocity of the particle is 0.8 ms^(-1) at x = 0, then velocity of the particle at x = 1.4 m is (in ms^(-1)) .

A graph of acceleration versus time of a particle starting from rest at t=0 is as shown in figure. The speed of the particle at t = 14s is

Displacement x versus t^(2) graph is shown for a particle. The acceleration of particle is

A particle moves along x-axis. At time t = 0 , the particle is at origin and its initial veclocity is along positive x-direction. The plot of its ("speed")^(2) versus its x-coordinate is as shown in graph. The time at which velocity of particle is zero.