A man drags a body of mass 200kg on a surface having coefficient of friction 0.1 through a distance 10m in 5 seconds.The power of man is ?

A body of mass 5 kg rests on a rough horizontal surface of coefficient of friction 0.2. The body is pulled through a distance of 10 m by a horizontal force of 25 N . The kinetic energy acquired by it is (g=10ms^(2))

When a body of mass M slides down an inclined plane of inclination theta , having coefficient of friction mu through a distance s, the work done against friction is :

A body of mass 2 kg is placed on a horizontal surface having coefficient of kinetic friction 0.4 and limiting coefficient of static friction 0.5. If a horizontal force 2.5 N is applied on the body, the frictional force acting on the body will be (Take, g = 10ms^(2) )

A block of mass 10kg is placed on a rough horizontal surface having coefficient of friction mu=0.5 . If a horizontal force of 100N is acting on it, then acceleration of the will be.

The work done in pulling a body of mass 5 kg along an inclined plane (angle 60^(@) ) with coefficient of friction 0.2 through 2 m, will be -

A body of mass 25 kg, is placed on a horizontal surface whose coefficient of friction 0.25. Find the frictional force action on it. Take ( g=10ms^(-2) )

A man carries a load of 50 kg through a height of 40 m in 25 seconds. If the power of the man is 1568 W , his mass is

A body of mass 2kg is placed on a horizontal surface having kinetic friction 0.4 and static friction 0.5 . If the force applied on the body is 2.5N , then the frictional force acting on the body will be

As shown in the figure, M is a man of mass 60 kg standing on a block of mass 40 kg kept on ground. The co-efficient of friction between the feet of the man and the block is 0.3 and that between B and the ground is 0.1. If the man accelerates with an acceleration 2(m)/(s^2) in the forward direction, then,