If `cos alpha=tan beta` and `cos beta=tan alpha` where `alpha` and `beta` are acute angles then `sin alpha`

If sin (alpha - beta) =1/2 and cos (alpha + beta) =1/2, where alpha and beta are positive acute angles, then alpha and beta are

(cos alpha-cos beta) / (sin beta-sin alpha) = tan ((alpha + beta) / (2))

sin alpha sin beta-cos alpha cos beta=1 then show that tan alpha+tan beta=0

If a tan alpha+b tan beta=(a+b)tan((alpha+beta)/(2)) where alpha!=beta ,prove that a cos beta=b cos alpha

If sin alpha sin beta-cos alpha cos beta+1=0, then prove that 1+cot alpha tan beta=0

If sin alpha+sin beta=a and cos alpha-cos beta=b then tan((alpha-beta)/(2))=

Evaluate: quad =|cos alpha cos beta cos alpha sin beta-sin alpha-sin beta cos beta0sin alpha cos beta sin alpha sin beta cos alpha|

If sin alpha sin beta-cos alpha cos beta+1=0 , then prove that 1+cotalpha tan beta=0 .

If sin alpha sin beta-cos alpha cos beta+1=0, then the value of 1+cot alpha tan beta is

Find the value of, cos alpha cos beta, cos alpha sin beta, -no alpha-sin beta, cos beta, 0 sin alpha cos beta, sin alpha sin beta, cos alpha] |