" For a projectile the ratio of the square of the time of flight to its maximum height is "

For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10 ms^(-2))

For a projectile if the time of flight is T , the maximum height is H and the horizontal range is R . Find the (a) the maximum height in terms of T and (b) the maximum horizontal range in terms of R and H .

Assertion In projectile motion, if time of flight is made two times, then maximum height will become four times. Reason T prop sin theta and H prop sin^(2) theta , where theta is angle of projection.

Range of a projectile with time of flight 10 s and maximum height 100 m is : (g= -10 m//s ^2)

Under what conditions the formulae of range, time of flight and maximum height can be applied directly in case of a projectile motion ?

The time of flight of the projectile is:

The launching speed of a certain projectile is five times the speed it has at its maximum height.Its angles of projection is

In a projectile motion, velocity at maximum height is

A projectile is thrown with velocity v at an angle theta with the horizontal. When the projectile is at a height equal to half of the maximum height,. The velocity of the projectile when it is at a height equal to half of the maximum height is.

Define time of flight for a projectile .