A galvanometer of resistance G can measure 1A current. if a shunt S in used to convert it into an ammeter to measure 10A current ratio of `(S)/(G)` is

A galvanometer having a resistance of 75 Omega gives the full scale deflection for the current of 25mA. The shunt required to convert it into an ammeter to measure the current up to 59 A is

A galvanometer has resistance G and full scale deflection current i. To convert this galvanometer into an ammeter of range 10 I, a shunt S = (G)/(9) is connected in parallel with G. Now we want to measure potential difference with the help of this ammeter. What is the maximum value of potential difference which can be measured with the help of this?

An ammeter of resistance 0.6Omega can measure current upto 1.0 A. Calculate (i) The shunt resistance required to enable the ammeter to measure current upto 5.0 A (ii) The combined resistance of the ammeter and the shunt.

A galvanometer of resistance 50Omega gives full scale deflection when a current 10^(-3)A is passed through it converted into an ammeter to measure 0.5A current.