A body of mass `(1)/(4) kg` moving with velocity `12 m//s` is stopped by applying a force of 0.6 N. Then impulse is :-

A body of mass 0.25 kg moving with velocity 12 m//s is stopped by applying a force of 0.6 N. Calculate the time taken to stop the body. Also calculate the impulse of this force.

5A body of mass 15 kg moving with a velocity of 10 m//s is to be stopped by a resistive force in 15 sec, the force will be -

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

A body of mass 4 kg moving with velocity 12 m//s collides with another body of mass 6 kg at rest. If two bodies stick together after collision , then the loss of kinetic energy of system is

0A body of mass 20 kg moving with a velocity of 3 m//s, rebounds on a wall with same velocity. The impulse on the body is -

A cricket ball of mass 0.2 kg moving with a velocity of 20 m/s is brought to rest by the player in 0.1 sec. Find the impulse of the force on the ball and average force applied by the player

A body moving with uniform velocity is stopped in 0.25 second by applying a retarding force of 200 Newton. The intial momentum of the body will be :-

A body moving with uniform velocity is stopped in 0.25 second by applying a retarding force of 200 Newton. The intial momentum of the body will be :-

A body moving with uniform velocity is stopped in 0.25 second by applying a retarding force of 200 Newton. The intial momentum of the body will be :-