Calculate the percentage error in specific resistance , `rho = pi r^(2) R // l `, where r = radius of wire `= 0.26 +- 0.02 cm` , l = length of wire `= 156.0 +- 0.1 cm`, and R = resistance of wire `= 64 +- 2 Omega`.

Find the percentage error in specific resistance given by rho = (pir^2R)/(l) where r is the radius having value (0.2+-0.02) cm, R is the resistance of (60+-2) ohm and l is the length of (150+-0.1) cm.

Find the percentage error in specific resistance given by rho = (pir^2R)/(l) where r is the radius having value (0.2+-0.02) cm, R is the resistance of (60+-2) ohm and l is the length of (150+-0.1) cm.

If 2x% be the percentage error in specific resistance given by rho=(pir^(2)R)/(l) where r is the radius having value (0.2 om 0.01) cm, R is the resistance of (60 pm 3) ohm and l is the length of (150 pm 1.5) cm. Find x.

The specific resistance rho of a circular wire of radius r , resistance R , and length l is given by rho = pi r^(2) R//l . Given : r = 0.24 +- 0.02 cm , R = 30 +- 1 Omega , and l = 4.80 +- 0.01 cm . The percentage error in rho is nearly

The specific resistance rho of a circular wire of radius r , resistance R , and length l is given by rho = pi r^(2) R//l . Given : r = 0.24 +- 0.02 cm , R = 30 +- 1 Omega , and l = 4.80 +- 0.01 cm . The percentage error in rho is nearly

Calculate the specific resistance of the material of a wire having a resistance of 4.4 Omega , length 1.1 m and radius 0.2 mm.

Resistance of wire having diameter 2 mm and length 100 cm is 0.7 Omega , so resistivity of wire = .....

The resistance of a wire of length 80 cm and of uniform area of cross-section 0.025 cm^2 , is found to be 1.50 ohm. Calculate the resistivity of the wire.

Resistance of wire having radius r is R. If new wire of radius 2r, is made, then the new resistance of wire = ......