`tan^(- 1)(a/b)-tan^(- 1)((a-b)/(a+b))=pi/4`

tan^(-1)((a)/(b))-tan((a-b)/(a+b))=(pi)/(4)

In a ABC, if C is a right angle,then tan^(-1)((a)/(b+c))+tan^(-1)((b)/(c+a))=(pi)/(3)(b)(pi)/(4)( c) (5 pi)/(2)( d) (pi)/(6)

If in triangleABC, tan^(-1)(a/(b+c))+ tan^(-1)(c/(a+b)) = pi/4 , then prove that, the triangle is right angled.

Prove that, tan^(-1)a+tan^(-1)b+tan^(-1)((1-a-b-ab)/(1+a+b-ab))=(pi)/(4) .

If in triangle ABC, C = 90^circ then prove that tan^(-1) (a/(c+b)) + tan^(-1) (b/(a+c)) = pi/4 .

In a triangle A B C , , if C is a right angle, then tan^(-1)(a/(b+c))+tan^(-1)(b/(c+a))= (a) pi/3 (b) pi/4 (c) (5pi)/2 (d) pi/6

tan ^ (- 1) ((a) / (b)) - tan ^ (- 1) ((ab) / (a + b)) = (pi) / (4)

tan^(-1)a+tan^(-1)b=(pi)/(2)

If C is a right angle in the triangle ABC, show that, tan^(-1) 'a/(b+c)' + tan^(-1) 'b/(c+a)' = pi/4 .

Prove that: tan[(pi)/(4)+(1)/(2) tan^(-1)((a)/(b))]+tan[(pi)/(4)-(1)/(2)tan^(-1)((a)/(b))]=(2sqrt(a^(2)+b^(2)))/(b)