Let n be a positive integer such that `sin(pi/2^n)+cos(pi/2^n)=sqrt n/2` ,then

Let n be a positive integer such that sin(pi/(2n))+cos(pi/(2n))=(sqrt(n))/2 Then

Let n be a positive integer such that sin (pi/(2n))+cos (pi/(2n))= sqrt(n)/2 then (A) n=6 (B) n=1,2,3,….8 (C) n=5 (D) none of these

Let n be a positive integer such that sin (pi/(2n))+cos (pi/(2n))= sqrt(n)/2 then (A) n=6 (B) n=1,2,3,….8 (C) n=5 (D) none of these

Let n be a fixed positive integer such that sin(pi/(2n))+cos(pi/(2n))=sqrtn/2 then

Let n be a positive integer such that sinpi/(2n)+cospi/(2n)=(sqrt(n))/2dot

Let n be a positive integer such that sin(pi/(2n))+cos(pi/(2n))=(sqrt(n))/2dot Then

Let n be a positive integer such that sin (pi/(2n))+cos(pi/(2n))=(sqrt(n))/2dot Then

Let n be a positive integer such that (sin pi)/(2n)+(cos pi)/(2n)=(sqrt(n))/(2)* Then 6<=n<=8(b)4

If n is positive integer and "cos" (pi)/(2n)+"sin" (pi)/(2n) =(sqrt(n))/(2) , then prove that 4 le n le 8

The number of positive integers which satisfy sin((pi)/(4n))+cos((pi)/(4n))=sqrt((n)/(2)) is -