[" If "alpha,beta,gamma" are the roots of "],[x^(3)-3x^(2)+4x-7=0," then "],[(alpha+2)(beta+2)(gamma+2)=]

If alpha,beta,gamma are the roots of x^(3)-2x^(2)+3x-4=0 then sum alpha beta(alpha+beta)=

If alpha,beta,gamma are the roots of x^(3)+2x^(2)-3x-1=0 then alpha^(-2)+beta^(-2)+gamma^(-2)=

If alpha,beta,gamma are the roots of x^(3)+2x^(2)+3x+8=0 then (alpha+beta)(beta+gamma)(gamma+alpha)=

If alpha , beta , gamma are the roots of x^3 +2x^2 +3x +8=0 then (3-alpha )(3 - beta) (3-gamma) =

If alpha , beta , gamma are the roots of x^3 +2x^2 +3x +8=0 then (3-alpha )(3 - beta) (3-gamma) =

If alpha, beta, gamma are the roots of x^(3) + x^(2) + x + 1 = 0 then (alpha - beta)^(2) + (beta - gamma)^(2) + (gamma - alpha)^(2) =

If alpha , beta , gamma are the roots of x^3 +2x^2 -3x -1=0 then alpha^(-2) + beta^(-2) + gamma^(-2)=

If alpha,beta,gamma are the roots of x^(3)-2x^(2)+3x-4=0 then the value of alpha^(2)beta^(2)+beta^(2)gamma^(2)+gamma^(2)alpha^(2) is

If alpha ,beta ,gamma are roots of x^(3)+x^(2)-5x-1=0 then [alpha] + [beta] +[ gamma ] is equal to