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tan^(-1)((cosx)/(1+sinx)) को सरल कीजिए |...

`tan^(-1)((cosx)/(1+sinx))` को सरल कीजिए |

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tan^-1((1+cosx)/(sinx))

tan^(-1)((1+sinx)/cosx)=

tan^(-1)((cosx+sinx)/(cos x-sinx))

d/(dx){tan^(-1)((cosx)/(1+sinx))}=

Find (dy)/(dx) , if y=tan^(-1)((cosx)/(1+sinx)) .

int tan^(-1)[(cosx)/(1-sinx)]dx=

At x=(pi)/(4),(d)/(dx)[tan^(-1)((cosx)/(1+sinx))]=

tan^(-1)[(cosx)/(1+sinx)] is equal to

"tan"^(-1)(1+sinx)/(cosx)=

tan^(-1) ((cosx - sinx)/(cosx + sinx)) , 0< x < pi