IF `S=1^2+3^2+5^2....99^2` then the value of the sum `2^2+4^2+6^2...100^2`

. Find the sum of the series 1.2+2.2^(2)+3.2^(2)+...+100.2^(100)

Sum of the series 1+2.2+3.2^2 +4.2^3+.....+100.2^99 is

Observe the following pattern 2^2-1^2=2+1 3^2-2^2=3+2 4^2-3^2=4+3 5^2-4^2=5+4 and find the value of (I) 100^2-99^2 (ii) 111^2-109^2 (iii) 99^2-96^2

Sum of the series 1+2.2+3.2^(2)+4.2^(3)+....+100.2^(99)is

Observe the following pattern 2^(2)-1^(2)=2+13^(2)-2^(2)=3+24^(2)-3^(2)=4+35^(2)-4^(2)=5+4 and find the value of 100^(2)-99^(2) (ii) 111^(2)-109^(2)99^(2)-96^(2)

Let S denote sum of the series 3/(2^3)+4/(2^4 .3)+5/(2^6 .3)+6/(2^7 .5)+ ...... oo Then the value of S^(-1) is __________.

Sum to n terms the series : 1^2 - 2^2 + 3^2 - 4^2 + 5^2 - 6^2 + ...

Sum of n terms the series : 1^2-2^2+3^2-4^2+5^2-6^2+....