Balls are thrown vertically upwards in such a way that the next ball is thorwn when the previous one is at the maximum height. If the maximum hieght is `5m`, the number of balls thrown per minute will be

A very large number of balls are thrown vertically upwards in quick successions in such a way that the next ball is thrown when the previous one is at the maximum height. If the maximum height is 5m, then number of balls thrown per minute is (take g=10m//s^(2) )

A very large number of balls are thrown verticlaly upwards in quick successions in such a way that the next ball is thrown when the previous one is at the maximum height. If the maximum height is 5m, the number of balls thrown per minute is (take g=10m//s^(2) )

In quick succession, a large number of balls are thrown up vertically in such a way that the next ball is thrown up when the previous ball is at the maximum height. If the maximum height is 5 m , then find the number of the balls thrown up per second (g=10 m s^(-2)).

In quick succession, a large number of balls are throun up vertically in such a way that the next ball is thrown up when the previous ball is at the maximum height. If the maximum height is 5 m , then find the mumber of the thrown up per second (g=10 m s^(-2)).

When a ball is thrown vertically upwards, at the maximum height

A ball is thrown vertically upwards with a certain velocity. Then

A ball is thrown vertically upwards. Its velocity keeps on decreasing. What happens to its kinetic energy when it reaches the maximum height ?