" If "tan theta=(3)/(4)" and "theta" is not in the first quandrant then "(sin(pi/2+theta)-cot(pi-theta))/(tan(3 pi/2-theta)-cos(3 pi/2+theta))

If tan theta = 3/4 and theta is not in the first quadrant then (sin (pi//2 + theta)-cot(pi-theta))/(tan(3 pi//2 - theta)-cos (3pi//2+theta))=

If tan theta=(3)/(4) and theta is not in first quadrant sin(sin((pi)/(2)+theta)-cot(pi-theta))/(tan((3 pi)/(2)-theta)-cos((3 pi)/(2)+theta))=

if cos theta=(3)/(5) and theta is not in the first quadrant then (5tan(pi+theta)+4cos(pi+theta))/(5sec(2 pi-theta)-4cot(2 pi+theta))=

If cos theta =(3)/5 and theta is not in the first quadrant , then (5 tan(pi+ theta ) + 4 cos (pi-theta ))/( 5 sec ( 2pi- theta ) - 4 cot (2pi+ theta ))=

Prove that : (cos(pi+theta)cos(-theta))/(sin (pi-theta) cos (pi/2+ theta))= cot^2 theta.

{(tan((pi)/(4)+theta)+tan((pi)/(4)-theta))/(tan((pi)/(4)+theta)-tan((pi)/( 4)-theta)))

tan (pi cos theta) = cot (pi sin theta)

If tan theta=-(3)/(4) and (pi)/(2)

If sin((pi cot theta)/(4))=cos((pi tan theta)/(4)) and theta is is in the first quadrant then theta=- and theta is is is