If `x=asectheta` and `y=btantheta` , then `b^2x^2-a^2y^2=` (a)`a b` (b) `a^2-b^2` (c) `a^2+b^2` (d) `a^2b^2`

If x=a sec theta and y=b tan theta, then b^(2)x^(2)-a^(2)y^(2)=( a )ab(b)a^(2)-b^(2)(c)a^(2)+b^(2) (d) a^(2)b^(2)

If x=acostheta and y=bsintheta , then b^2x^2+a^2y^2= (a) a^2b^2 (b) a b (c) a^4\ b^4 (d) a^2+b^2

x=a sin theta , y=btantheta so prove that a^2/x^2-b^2/y^2=1

If x=asintheta and y=btantheta, then prove that (a^2)/(x^2)-(b^2)/(y^2)=1

If x=a cos theta and y=b sin theta, then b^(2)x^(2)-a^(2)y^(2)=a^(2)b^(2)( b) ab(c)a^(4)b^(4)(d)a^(2)+b^(2)

If x=asectheta,y=btantheta,"prove that"(d^2y)/(dx^2)=-(b^4)/(a^2y^3)

If x=a sec theta , y=b tantheta , then x^2/a^2-y^2/b^2 is (A) -1 (B) 0 (C) 1 (D) 2

If x=asectheta , y=btantheta , prove that (d^2y)/(dx^2)=-(b^4)/(a^2\ y^3) .

If x=asectheta,y=btantheta, then the value of x^(2)/a^(2)-y^(2)/b^(2)= …….. .