The wavelength of maximum energy released during an atomic axplosion was `2.93xx10^(-10)m`. Given that Wien's constant is `2.93xx10^(-3)m-K`, the maximum temperature attained must be of the order of

The wavelength of maximum energy released during an atomic explosion was 2.93 x 10^(-10) m. Given that Wein's constant is 2.93 xx 10^(-3) m-K, the maximum temperature attained must be of the order of

If the wavelength corresponding to maximum energy radiated from the moon is 14 micron, and wien's constant is 2.8xx10^(-3)mK , then temperature of moon is

If the wavelength corresponding to maximum energy radiated from the moon is 14 micron, and wien's constant is 2.8xx10^(-3)mK , then temperature of moon is

If the wavelength corresponding to maximum energy radiated from the moon is 14 micron , and Wien 's constant is 2.8 xx 10^(-3) m K , then temperature of moon is

Light from the moon, is found to have a peak (or wevelenght of maximum emission) at lambda = 14 mu m . Given that the Wien's constant b equals 2.8988 xx 10^(-3) mK , estimate the temperature of the moon.

For the moon, the wavelength corresponding to the maximum spectral emissive power is 14 microns. If the Wien's constant b=2.884 xx10^(-3)mK , then the temperature of the moon is close to

the maximmum temperature reached during an atomic explosion was of the order of 10^(7) K. Calculate the wavelength of maximum energy b = 0.293 cm K.