[2x-3y=7],[(a+b)x-(a+b-3)y=4a+b]

Find the values of a and b for which the following system of linear equations has infinite number of solutions: 2x-3y=7,quad (a+b)x-(a+b-3)y=4a+b

If 2x-3y=7 and (a+b)x-(a+b-3)y=4a+b represent coqucident lines,then a and b satisfy the equation?

If 2x-3y=7 and (a+b)x-(a+b-3)y=4a+b represent coincident lines, then a and b satisfy the equation (a) a+5b=0 (b) 5a+b=0 (c) a-5b=0 (d) 5a-b=0

If 2x-3y=7 and (a+b)x-(a+b-3)y=4a+b represent coincident lines,then a and b satisfy the equation a+5b=0 (b) 5a+b=0 (c) a-5b=0 (d) 5a-b=0

If 2x-3y=7" and "(a+b)x-(a+b-3)y=4a+b represent coincident lines, then a and b satisfy the equation :

2x+3y=7(a+b)x+y(2a-b)=3(a+b+1) find the value of a+b

2x + 3y = 7& (a-b)x+ (a + b) y = 3a + b-2

2x + 3y =7 , (a + b ) x + ( 2a - b ) y = 21 .

Factorize each of the following algebraic expressions: x^(3)(a-2b)+x^(2)(a-2b)2x-3y)(a+b)+(3x-2y)(a+b)4(x+y)(3a-b)+6(x+y)(2b-3a)