`x^2+2x-35`

log_e ((1+3x)/(1-2x)) is equal to a) -5x-(5x^2)/2-(35x^3)/3-... b) -5x+(5x^2)/2-(35x^3)/3-... c) 5x-(5x^2)/2+(35x^3)/3-... d) 5x+(5x^2)/2+(35x^3)/3-...

Factorize the following polynomials. (x^2 -2x+3)(x^2 -2x+5)-35

Factorize the polynomial. (^2-2x+3)(x^2-2x+5)-35

If the lines x^2+2x y-35 y^2-4x+44 y-12=0a n d5x+lambday-8 are concurrent, then the value of lambda is

If the lines x^2+2x y-35 y^2-4x+44 y-12=0&5x+lambday-8=0 are concurrent, then the value of lambda is (a) 0 (b) 1 (c) -1 (d) 2

If the lines x^2+2x y-35 y^2-4x+44 y-12=0&5x+lambday-8=0 are concurrent, then the value of lambda is (a)0 (b) 1 (c) -1 (d) 2

Factorise : x^(3)-6x^(2)+12x-35

If x^(2)+2x-5 is a factor of x^(4)-2x^(3)+px^(2) +qx-35 , then find the value of p^(2)-q .