[" Three randomly chosen non-negative integers "x,y" and "z" are found to satisfy the equation "x+y+z=10" .Then "],[" he probability that "z" is even,is "]

Three randomly chosen nonnegative integers x,y and z are found to satisfy the equation x+y+z=10. Then the probability that z is even,is: (5)/(12) (b) (1)/(2)( c) (6)/(11) (d) (36)/(55)

Three randomly chosen nonnegative integers x , ya n dz are found to satisfy the equation x+y+z=10. Then the probability that z is even, is: 5/(12) (b) 1/2 (c) 6/(11) (d) (36)/(55)

Three randomly chosen nonnegative integers x , ya n dz are found to satisfy the equation x+y+z=10. Then the probability that z is even, is: 5/(12) (b) 1/2 (c) 6/(11) (d) (36)/(55)

Three randomly chosen nonnegative integers x , ya n dz are found to satisfy the equation x+y+z=10. Then the probability that z is even, is: 5/(12) (b) 1/2 (c) 6/(11) (d) (36)/(55)

Two non-negative integers x and y are chosen at random with replacement. The probability that x^(2)+y^(2) is divisible by 10, is

The number of non- negative integral solutions of the equation x + y + z = 5 is :

The number of non- negative integral solutions of the equation x + y + z = 5 is :

Find the number of non-negative integral solutions of the equation x+y+z=10 .

The number of non-negative integral solutions of the equation x^(2)+y+z=10 is