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If (x^y)^z = x^y ^ ^z where each of x, y...

If `(x^y)^z` = `x^y`` ^ ^z` where each of x, y and z is greater than 1, then find y in terms of z.

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Given, `(x^(y))^(z)=x^(y^(z))`
`implies x^(y^(z))=x^(y^(z))`
`implies yz=y^(z)`
`implies z=y^(z-1)`
`implies y= z^(1/(z-1))`
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