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PEARSON IIT JEE FOUNDATION-INDICES-CONCEPT APPLICATION LEVEL 1
- [169^(-3)/((196)^(-8))]^(1/48)=
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- How do you find the value of x² + 1/x² given that x = 2+ √3?
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- 81^(1/4)xx9^(3//2)xx27^(- 4/3)=
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- If 4(4x)^(7)=4^(6^(2)), then what is the value of x ?
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- If 7^(n)=2401, then 7^(n-5)=
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- root(5)(0.03125)=
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- Find the value of (225/49)^(3//2).
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- Find the value the value of 3^(2^(r^(0^(-1^(-2^(-3))))))
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- 4xx(256)^((-1)/4) div (243)^(1/5)=
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- Find the value of (0.000064)^(2/3) div (0.0016)^(3/4).
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- If 6^n=1296, then 6^(n-3) is
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- The value of (9^(2)+40^(2))^(3/2)=
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- [(8^(@)-7^(@))(8^(@)+7^(@))]^(0^(7^(8)))=
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- Value of (125/343)^(2/3)=
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- If (81)^(x)=1/((125)^(y)) and x, y are integers, then find the value o...
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- If (6x)^(6)=6^(2^(3)), then find the value of x.
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- Find the value of (6561)^((0.125))+(3125)^((0.2)).
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- Find the value of (256)^((0.125))+(625)^((0.25))
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- Evaluate the following sqrt(1/16)+(0.09)^((-1)/2)-(64)^(5/6)xx7^(@).
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- If x^y = 64 , where y!= 1, find the sum of greatest possible value of ...
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