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A and B can do a work in 30 days and 10 ...

A and B can do a work in 30 days and 10 days respectively. If they work on alternate days beginning with A, in how many days will the work be completed?

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To solve the problem step by step, we will analyze the work done by A and B, who work on alternate days, starting with A. ### Step 1: Determine the work done by A and B in one day. - A can complete the work in 30 days. Therefore, A's work in one day is: \[ \text{Work done by A in one day} = \frac{1}{30} \text{ of the work} \] - B can complete the work in 10 days. Therefore, B's work in one day is: \[ \text{Work done by B in one day} = \frac{1}{10} \text{ of the work} \] ### Step 2: Calculate the total work done in two days (one cycle of A and B). - In the first day, A works: \[ \text{Work done by A} = \frac{1}{30} \] - In the second day, B works: \[ \text{Work done by B} = \frac{1}{10} \] - Therefore, the total work done in two days is: \[ \text{Total work in 2 days} = \frac{1}{30} + \frac{1}{10} \] To add these fractions, we need a common denominator (which is 30): \[ \frac{1}{10} = \frac{3}{30} \] So, \[ \text{Total work in 2 days} = \frac{1}{30} + \frac{3}{30} = \frac{4}{30} = \frac{2}{15} \] ### Step 3: Determine how many complete cycles are needed to finish the work. - The total work is considered as 1 unit. To find out how many cycles (2 days) are needed to complete the work, we can set up the equation: \[ \text{Number of cycles} = \frac{1 \text{ unit of work}}{\frac{2}{15} \text{ unit of work per cycle}} = \frac{15}{2} = 7.5 \text{ cycles} \] ### Step 4: Calculate the total days taken. - Each cycle takes 2 days, so: \[ \text{Total days for 7 complete cycles} = 7 \times 2 = 14 \text{ days} \] - In 14 days, the work done is: \[ \text{Work done in 14 days} = 7 \times \frac{2}{15} = \frac{14}{15} \] ### Step 5: Calculate the remaining work and the last day. - The remaining work after 14 days is: \[ \text{Remaining work} = 1 - \frac{14}{15} = \frac{1}{15} \] - On the 15th day, A will work again (since they alternate days). A can complete: \[ \text{Work done by A on 15th day} = \frac{1}{30} \] - However, A can only complete \(\frac{1}{15}\) of the work, which is less than \(\frac{1}{30}\). Thus, A will finish the remaining work. ### Step 6: Total days to complete the work. - The total days taken to complete the work is: \[ \text{Total days} = 14 + 1 = 15 \text{ days} \] ### Final Answer: The work will be completed in **15 days**. ---
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