Home
Class 8
MATHS
The capacities of A,B and C to complete ...

The capacities of A,B and C to complete a piece of work is `1:2:3`. By working together, the thre of them can complete the work in 24 days. In how many days can C alone complete it ?

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Understand the Ratios of Work Capacities The work capacities of A, B, and C are given in the ratio of 1:2:3. This means: - A's work capacity = 1 part - B's work capacity = 2 parts - C's work capacity = 3 parts ### Step 2: Calculate Total Work Capacity To find the total work capacity, we add the parts together: - Total capacity = A + B + C = 1 + 2 + 3 = 6 parts ### Step 3: Determine Work Done Per Day If A, B, and C can complete the work together in 24 days, then the total work done in terms of capacity can be calculated as follows: - Work done in 1 day = Total work / Total days = 1 (complete work) / 24 days = 1/24 of the work per day. ### Step 4: Relate Daily Work to Capacity Since the total capacity is 6 parts, the work done by A, B, and C together in one day can also be expressed as: - Work done in 1 day = Total capacity = 6 parts. ### Step 5: Calculate Work Done by C Alone Now, we need to find out how many days C alone would take to complete the work. C's capacity is 3 parts. To find the number of days C would take to complete the entire work, we can set up the following equation: - If C does 3 parts of work in one day, then the number of days C would take to complete the entire work (6 parts) is given by: \[ \text{Days taken by C} = \frac{\text{Total work}}{\text{C's capacity}} = \frac{6 \text{ parts}}{3 \text{ parts/day}} = 2 \text{ days} \] ### Step 6: Calculate Total Days for C Alone Since we know that A, B, and C together complete the work in 24 days, we can use the relationship between their capacities and the total days: - Total days for C alone = 24 days (for 6 parts) multiplied by (Total capacity / C's capacity) \[ \text{Days taken by C} = 24 \times \frac{6}{3} = 24 \times 2 = 48 \text{ days} \] ### Final Answer C alone can complete the work in **48 days**. ---
Promotional Banner

Topper's Solved these Questions

  • TIME AND WORK PIPES AND CISTERNS

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (LEVEL-1)|33 Videos
  • TIME AND WORK PIPES AND CISTERNS

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (LEVEL-2)|20 Videos
  • TIME AND WORK PIPES AND CISTERNS

    PEARSON IIT JEE FOUNDATION|Exercise Short Answer Type Questions|15 Videos
  • TIME AND DISTANCE

    PEARSON IIT JEE FOUNDATION|Exercise Concept Application (Level 2 )|3 Videos
  • TIME AND WORK, PIPES AND CISTERNS

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (LEVEL-3)|7 Videos

Similar Questions

Explore conceptually related problems

A is twice as fast as B and together they can complete a work in 20 days. In how many days can A alone complete the work?

A is twice as fast as B and together they can complete a work in 20 days. In how many days can A alone complete the work?

A, B and C can complete a piece of work in 10, 20 and 60 days respectively. Working together they can complete the same work in how many days?

A and B together can complete a piece of work in 4 days. If A alone can complete the same work in 12 days, in how many days can B alone complete that work ?