A light ray from an object 'P' is reflected from a mirror as shown in the figure, then

Options

A. angle of incidence is `30^(@)`
B. `PM=MP^(1)`
C. `anglePON=120^(@)`
D. All the above.

Answer

D

Explanation

(i) From figure
`angleTON=90^(@)`
`:.angleTOQ=angler=90^(@)-60^(@)=30^(@)` `:.` angle of reflection `30^(@)`.
But accoding to the laws of reflection, the angle of incidence (i) = the angle of reflection (r). `:.i=30^(@)`
(ii) In case of a plane mirror, object distance=image distance.
(iii) `anglePON=anglePOQ+angleQON`
`=30^(@)+30^(@)+60^(@)`
`=120^(@)`