" Check if a natural number "n" Of लिए,संख्या "6" numbers "0" But can be finished. "

If n is a natural number, then sqrt(n) is:

N is a least natural number having 24 divisors. Then the number of ways N can be resolved into two factors is

If n is an (a) odd natural number greater than 1, then the product of its successor and predecessor is an odd natural number (b) is an even natural number (c) can be even or odd (d) None of these

If n is an odd natural number greater than 1 then the product of its successor and predecessor is an odd natural number (b) is an even natural number can be even or odd (d) None of these

If A={4n+2|n " is a natural number"} and B={3n|n " is a natural number"} , then what is (AnnB) equal to?

If n is an even natural number, then the product of its successor and predecessor (a) is an even natural number (b) is an odd natural number (c)can be even or odd (d) None of these

The set (0,2,6,12,20) in the set-builder form is (1) {x:x=n^(2)-3n+2," where "n'" is a natural number "&1 (2) {x:x=n^(2)-3n+2," where "'n'" is a natural number "&1 (3) {x:x=n^(2)-3n+4," where "'n'" is a natural number "&1 (4) {x:x=n^(2)+5n-6," where 'n' is a natural number "&1<=n<=5}

The number of natural numbers n for which (15n^2+8n+6)/n is a natural number is:

Consider the number 4^n where n is a natural number. Check whether there is any value of n which 4^n ends with the digit zero?