[" Let "f(x,y)=0" be the equation of a circle.If "],[f(0,k)=0" has equal roots "k=2,2" and "],[f(k,0)=0" has roots "k=(4)/(5),5," then the "],[" centre of the circle is "]

Let f(x,y)=0 be the equation of a circle. If f(0,lamda)=0 has equal roots lamda=2,2 and f(lamda,0)=0 has roots lamda=(4)/(5),5 then the centre of the circle is

Let f(x,y)=0 be the equation of a circle. If f(0,lamda)=0 has equal roots lamda=2,2 and f(lamda,0)=0 has roots lamda=(4)/(5),5 then the centre of the circle is

Let phi(x,y)=0 be the equation of a circle. If phi(0,lamda)=0 has equal roots lamda=2,2fandphi(lamda,0)=0 has roots lamda=(4)/(5),5 then the centre of the circle is

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/2 ,2, then the centre of the circle is

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/2 ,2, then the centre of the circle is

Let f(x,y)=0 be the equation of circle.If f(0,lambda)=0 has equal roots lambda=1,1 and f(lambda,0)=0 has roots lambda=(1)/(5),5 ,then the radius of the circle

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/5 ,5, then the radius of the circle is

Let phi (x,y)=0 , be the equation of circle. If phi (0,lambda)=0 has equal roots lambda =2,2 and phi (lambda,0)=0 has roots lambda=4/5, 5 then the centre of the circle is :

f(x , y)=x^2+y^2+2a x+2b y+c=0 represents a circle. If f(x ,0)=0 has equal roots, each being 2, and f(0,y)=0 has 2 and 3 as its roots, then the center of the circle is