If ` f(x) ={(x^(3)", " x lt1),(2x-1", " x ge 1):} " and " g(x)={(3x", " x le2),(x^(2)", " x gt 2):} " then find " (f-g)(x).`

Explanation

` f(x) ={(x^(3)", " x lt1),(2x-1", " 1 le x le 2),(2x-1", " x gt 2):} " and " g(x)={(3x", " x lt1),(3x", "1 le x le2),(x^(2)", " x gt 2):}`
` implies (f+g)(x) ={(x^(3)+3x", " x lt1),(2x-1+3x", " 1 le x le 2),(2x-1+x^(2)", " x gt 2):}`
`={(x^(3)+3x", " x lt1),(5x-1", " 1 le x le 2),(x^(2)+2x-1", " x gt 2):}`