Find the range of the function `f(x)=3 sin (sqrt((pi^(2))/(16)-x^(2))).`

Explanation

To find the range of the function \( f(x) = 3 \sin\left(\sqrt{\frac{\pi^2}{16} - x^2}\right) \), we will follow these steps:

### Step 1: Determine the domain of the function
The expression inside the square root must be non-negative for the function to be defined. Therefore, we need to solve the inequality:

\[ \frac{\pi^2}{16} - x^2 \geq 0 \]
...