Light of wavelength 5000 Å is incident on a double with and the interference fringes are formed on a screen plated at a distance of 1m from the slits. If the distance between the two consecutive dark bands is 1 mm, then the distance between the two slits is

Light of wavelength 5000 overset@A , is incident on a double slit Young.s experiment. If the overall separation of 10 fringes on a screen 200 cm away is 1.0 cm, calculate the distance between the two slits.

Light of wavelength 5000Å is incident normally on a slit. First minimum of diffraction pattern is formed at a distance of 5 mm from the central maximum. If slit width is 0.2 mm, then distance between slit and screen will be :

Two slits separated by a distance of 0.5 mm are illuminated by light of wavelength 5000 Å. The interference fringes are obtained on a screen at a distance of 1.2 m. what is the phase difference between two interfering waves at a point 3 mm from the central bbright fringe?

Two slits separated by a distance of 0.5 mm are illuminated by light of wavelength 5000 Å. The interference fringes are obtained on a screen at a distance of 1.2 m. what is the phase difference between two interfering waves at a point 3 mm from the central bright fringe?

In youngs double slit experiment the fringes are formed at a distance of 1m from double slits of sepration 0.12mm .calculate the distance of 4th dark band from the centre of screen ?(wavelength is 12000A).

A beam of light consisting of two wavelengths, 6500 Å and 5200 Å is used to obtain interference fringes in a Young's double slit experiment (1 Å = 10^(-10) m). The distance between the slits is 2.0 mm and the distance between the plane of the slits and the screen in 120 cm. (a) Find the distance of the third bright fringes on the screen from the central maximum for the wavelength 6500 Å (b) What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide ?