Solve `(x-2)[x]={x}-1.`

Answer

`[1,2)`

Explanation

For `x ge 2`, LHS is always non-negative and RHS is always negative.
Hence, for `x ge 2`, there is no solution.
If `1 le x lt 2, " then " (x-2)=(x-1)-1=x-2,` which is an identity.
For `0 le x lt 1,` LHS is 0 and RHS is (-)ve.
So, there is no solution.
Hence, `x in [1,2).`