[p^(n)=(a times5)^(n)" For "p^(n)" to end with the digit zero "a=],[[" (a) any natural number "," (b) even number "],[" (b) odd number "," (d) none of these "]]

p^(n)=(axx5)^(n) For p^(n) to end with the digit zero a- ________________ for natural number of n.

Show that 3^(n) xx 4^(m) cannot end with the digit 0 or 5 for any natural numbers ‘n’and 'm'

Show that 3^(n) xx 4^(m) cannot end with the digit 0 or 5 for any natural numbers ‘n’and 'm'

Show that 3^(n) xx 4^(m) cannot end with the digit 0 or 5 for any natural numbers ‘n’and 'm'

Show that 3^(n) xx 4^(m) cannot end with the digit 0 or 5 for any natural numbers ‘n’and 'm'

If 6^n - 5^n always end with a digit, where n is any natural number, then the desired digit is

Assertion (A): 6^(n) ends with the digit zero where n is a natural number. Reason (R):Any number ends with digit zero, if its prime factor is of the form 2^(m)xx5^(n) , where m,n are natural numbers.

Can we have any n varepsilon N, where 15^(n) ends with the digit zero?

If ""^(n)P_(5)=9times^(n-1)P_(4), then the value of n is

Prove that there is no natural number for which 4^(n) ends with the digit zero.